Math, asked by swapnalpandep7j8vf, 1 year ago

Sum of the present ages of manish and savita is 31. Manish's age 3 years ago was 4 times the age of savita. Find their present age

Answers

Answered by sarthakkhurana8
4
Here is ur answer
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Answered by wifilethbridge
0

Answer:

Present age of savita is 8 years

Present age of manish is 23 years

Step-by-step explanation:

GIVEN : Sum of the present ages of Manish and Savita is 31. Manish's age 3 years ago was 4 times the age of Savita.

To Find:  Find their present age

Solution :

Let the present age of manish be x years

Let present age of savita be y years

Since we are given that  Sum of the their present ages is 31

x+y=31 --a

We are also given that Manish's age 3 years ago was 4 times the age of Savita.

Manish's age 3 years ago = x-3

Savita's age 3 years ago = y-3

Now x-3=4(y-3)

x-3=4y-12

x-4y+9=0--b

Solving a and b

Substitute value of x from a in b

31-y-4y+9=0

40-5y=0

40=5y

y=\frac{40}{5}

y=8

Thus the present age of savita is 8 years

So age of manish is 31-8=23 years

Hence the present age of manish is 23 years



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