Question

Sum of the present ages of Saikia and Paul is 29 years. If Saikia is younger and the difference of their ages 3 years ago was 5 years, find their ages two years from now

Answer 1

Answer:

let the present age of saikia be ' x ' and Paul be ' y'.

by 1st condition,

x+y=29

by 2nd condition,

(y-3)-(x-3)=5

y-3-x+3=5

y-x=5

-x+y=5

now,adding condition 1and 2

x+y=29

+-x+y=5

2y=34

y=34÷2

y=17

y=17 put in condition 1st

x+y=29

x+17=29

x=29-17

x=12

hence, present age of saikia is12 years

and present age of Paul is 17 years

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Answer 2

Step-by-step explanation:

Attached below... hope it helps