) Sum of the present ages of Teena and Meena is 31. Teena’s age 3 years ago
was 4 times the age of Meena. Find their present ages.
Answers
Answer :
The present age of Teena = 23 years
The present age of Meena = 8 years
Step-by-step explanation :
Given :
- Sum of the present ages of Teena and Meena is 31.
- Teena’s age 3 years ago was 4 times the age of Meena
To find :
- The present ages of Teena and Meena.
Solution :
Let
the present age of Teena be x years
the present age of Meena be y years
Sum of their present ages = 31
x + y = 31 ➙ [1]
3 years ago,
Teena's age = (x - 3) years
Meena's age = (y - 3) years
Teena’s age was 4 times the age of Meena
x - 3 = 4(y - 3)
x - 3 = 4y - 12
4y - x = 12 - 3
4y - x = 9 ➙ [2]
Add both the equations,
x + y + 4y - x = 31 + 9
5y = 40
y = 40/5
y = 8
Substitute y = 8 in equation [1],
x + y = 31
x + 8 = 31
x = 31 - 8
x = 23
Therefore,
the present age of Teena = 23 years
the present age of Meena = 8 years
Answer:
♥️
The present age of Teena = 23 years
The present age of Meena = 8 years
Step-by-step explanation :
Given :
Sum of the present ages of Teena and Meena is 31.
Teena’s age 3 years ago was 4 times the age of Meena
To find :
The present ages of Teena and Meena.
Solution :
Let
the present age of Teena be x years
the present age of Meena be y years
Sum of their present ages = 31
x + y = 31 ➙ [1]
3 years ago,
Teena's age = (x - 3) years
Meena's age = (y - 3) years
Teena’s age was 4 times the age of Meena
x - 3 = 4(y - 3)
x - 3 = 4y - 12
4y - x = 12 - 3
4y - x = 9 ➙ [2]
Add both the equations,
x + y + 4y - x = 31 + 9
5y = 40
y = 40/5
y = 8
Substitute y = 8 in equation [1],
x + y = 31
x + 8 = 31
x = 31 - 8
x = 23
Therefore,
the present age of Teena = 23 years
the present age of Meena = 8 years