Question

Sum of the present ages of two friends are 23 years, five years agº proud
of their ages was 42. Find their ages 5 years hence.
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Answer 1

Answer:

Step-by-step explanation:

let x and y be the present ages of the friends

given

x + y = 23

y = 23 - x ------- 1

( x -5 ) ( y - 5 ) = 42

xy - 5x - 5y + 25 = 42

x(23 - x) - 5x - 5(23 - x) + 25 - 42 = 0          [ from 1 ]

23x - x² - 5x - 115 + 5x - 17 = 0

-x² + 23x - 132 = 0

x² - 23x + 132 = 0

( x - 11 ) ( x - 12 ) = 0

x = 11 or 12

∴ their present ages are 11 and 12

Answer 2

Please see the attachment