Math, asked by poosalaabhisri, 1 year ago

sum of the present ages of two friends are 23 years five years ago product of their ages was 42 find their ages five year hence

Answers

Answered by goru07

This question came today in our public exam
I wrote it perfectly

poosalaabhisri: i too

poosalaabhisri: but i want to verify

poosalaabhisri: i want answer

poosalaabhisri: plz

goru07: but finally the answer was 11 years and 12 years

poosalaabhisri: will u provide brief explanation

Anonymous: If it is 5 yeras hence, the answer has to be 16,17

Anonymous: years*

poosalaabhisri: hey i need process

Anonymous: The process is given below. Kindly check

Answered by Anonymous

Step-by-step explanation:

Let the ages of friends 5 years ago be X , Y

ATQ:

5 years ago,

X * Y = 42 ...(i)

Now, X +5 + Y+5 = 23

X + Y = 13 .... (ii)

X = 13-Y ...(iii)

(iii) in (i)

(13-Y)*Y = 42

13Y - Y² = 42

Y² - 13Y + 42 = 0

Sum = -13 && product = 42

Numbers are -6,-7

Y² - 6Y - 7Y +42 = 0

Y(Y-6) -7(Y-6) = 0

[Y-6][Y-7] = 0

Y = 6 or Y =7

When Y = 6, X = 7

and Y = 7, then, X = 6

Ages 5 years ago = 6,7

At present = 6+5 , 7+5

5 years hence = 6+5+5 , 7+5+5 = 16 , 17

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