Question

Sum of the present ages of two friends are 23 years , five years ago product of their two ages was 42 find their ages 5 years hence

Answer 1

Answer:

Five years hence their ages will be

17 and 16

Step-by-step explanation:

Let their present ages be x and y.

As per given data,

x+y=23...........(1)

Five years ago

(x-5)(y-5)=42

xy-5(x+y)+25=42

xy-5(23)+25=42

xy-115+25=42

xy=132...........(2)

Now we solve (1) and (2)

x+y=23........(1)

xy=132........(2)

by trial and error method

we get x= 12 and y=11

Five years hence their ages will be

17 and 16