Sum of the resistances is 5 ohm & the product of the resistances is 6 ohm. The equivalent resistances in the series & parallel respectively will be
(a)5 ohm, 6/5 ohm
(b)6/5 ohm, 5 ohm
(c)5 ohm, 5/6 ohm
(d)6/5 ohm, 5/6 ohm
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Answer:
Rs = 5 ohm and Rp = 6/5 ohm
Explanation:
We are given,
R1 + R2 = 5 ohm
R1 × R2 = 6 ohm
Now,
If connected in Series Rs = R1 + R2
Thus,
Rs = 5 ohm
Now,
If connected in Parallel
(1/Rp) = (1/R1) + (1/R2)
(1/Rp) = (R1 + R2)/(R1 × R2)
Rp = (R1 × R2)/(R1 + R2)
Thus,
Rp = 6/5 ohm
Thus,
Rs = 5 ohm and Rp = 6/5 ohm
Hope it helped and you understood it........All the best
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