Question

sum of the roots is 6 and product is 3 find the quad equation​

Answer 1

Answer:

Sum of the roots, s = 6

Product of the roots, p = 3.

The required quadratic equation is

${x}^{2} - sx + p = 0 \\ {x}^{2} - 6x + 3 = 0$

Answer 2

Answer:

Let the polynomial be k(ax^2+bx+c) where k is the constant.

Let a=1

Sum of the roots= -b/a= 6

=> b= -6

Product of the roots= c/a= 3

=> c= 3

Therefore,

k(ax^2+bx+c)

=k(x^2-6x+3)

=x^2-6x+3 [When k=1]