Sum of the roots of a quadratic equation is double their product. Find k if equation is x square -4kx+k+3=0
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Answered by
10
Hi...☺
Here is your answer...✌
Given equation :
x² - 4kx + k + 3 = 0
⇒ a = 1 , b = -4k , c = k+3
Given that,
Sum of roots = 2×Product of roots
-b/a = 2×c/a
-b = 2c
⇒ -(-4k) = 2(k+3)
⇒ 4k = 2k + 6
⇒ 4k - 2k = 6
⇒ 2k = 6
⇒ k = 3
Here is your answer...✌
Given equation :
x² - 4kx + k + 3 = 0
⇒ a = 1 , b = -4k , c = k+3
Given that,
Sum of roots = 2×Product of roots
-b/a = 2×c/a
-b = 2c
⇒ -(-4k) = 2(k+3)
⇒ 4k = 2k + 6
⇒ 4k - 2k = 6
⇒ 2k = 6
⇒ k = 3
Answered by
2
your answer is k = 1
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