Question

Sum of the roots of the equation 12x^2-7x+1=0 is

Answer 1

Answer:

${12x}^{2} - 7x + 1 = 0 \\ = {12x}^{2} - 3x - 4x+ 1 = 0\\ = 3x(4x - 1) - 1(4x - 1) = 0\\ = (4x - 1) (3x - 1) = 0 \\ x = \frac{1}{4} \\ x = \frac{1}{3}$

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