Question

Sum of the roots of the equation 4* – 3(2* + 3) + 128 = 0, is:

a)0
b)7
c)5
d)8​

Answer 1

Answer:

refer to the attachment

Answer 2

Answer:

Given equation

4x−3(2x+3)+128=0

⇒(22)x−3(2x⋅23)+128=0

⇒(2x)2−3(2x⋅8)+128=0

Taking 2x=y the equation becomes

⇒y2−24y+128=0

⇒y2−16y−8y+128=0

⇒y(y−16)−8(y−16)=0

⇒(y−16)(y−8)=0

So y=8andy=16

when y=8⇒2x=23⇒x=3

when y=16⇒2x=24⇒x=4

Hence roots are 3 and 4

now 3 +4 = 7