Question

sum of the roots of the kx2+3x+1=0 is 3 then k =

Answer 1

Step-by-step explanation:

x2+kx−6 = 0

32+k·3−6 = 0

9+3k−6 = 0

3+3k = 0

3k = −3

k = −1

Since Quantity A (k) is −1, we can see that both quantities are equal. Sothe correct answer is C, the two quantities are equal.

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Answer 2

Answer:

Required value of k is (-1)

Step-by-step explanation:

Given,

$k {x}^{2} + 3x + 1 = 0......(1)$

We know,

$a {x}^{2} + bx + c = 0$ is a equation then sum of roots of the equation is $(- \frac{b}{a})$

and product of roots of the equation is $\frac{c}{a}$

We are comparing equation (1) with

$a {x}^{2} + bx + c = 0$

and get,

$a = k\\ b = 3 \\ c = 1$

So according to rule sum roots

$= - \frac{3}{k}$

It is given that sum of roots is 3.

According to question,

$- \frac{3}{k} = 3$

By cross multiplication,

$3k = - 3 \\ k = - 1$

Equation related two more questions:

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