sum of the serial nos 1 to 50
Answers
Answered by
0
Hi Friend !!!
Here is ur answer !!
a = 1 , n, 50 , an = 50
Sn = n/2 ( a+an)
= 50/2 (1+50)
= 25(51)
= 1275
Hope it helps u :-)
Here is ur answer !!
a = 1 , n, 50 , an = 50
Sn = n/2 ( a+an)
= 50/2 (1+50)
= 25(51)
= 1275
Hope it helps u :-)
Answered by
3
There’s a formula to calculate the sum of the first n natural numbers:
(n(n+1))/2
Let’s take n=3 as an example; we know that 1+2+3 = 6. Let’s put it in the equation to check whether the equation works:
(3(3+1))/2
=(3(4))/2
=(12)/2
=6
Now that we know it works, we take n as 50:
(50(50+1))/2
=(50(51))/2
=(2550)/2
=1275
So, the sum of the first 50 natural numbers is 1275
(n(n+1))/2
Let’s take n=3 as an example; we know that 1+2+3 = 6. Let’s put it in the equation to check whether the equation works:
(3(3+1))/2
=(3(4))/2
=(12)/2
=6
Now that we know it works, we take n as 50:
(50(50+1))/2
=(50(51))/2
=(2550)/2
=1275
So, the sum of the first 50 natural numbers is 1275
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