Question

sum of the series 222+224+224....+888 (a) 185370
(b) 195300
(d) 899000. ( c) 183000​

Answer 1

Answer:

a) 185370

Step-by-step explanation:

a = 222, d = 2, last term = 888

number of terms = an = a + (n-1)d

888 = 222 + (n-1)2

888 - 222 = (n-1)2

666 = (n-1)2

666/2 = n - 1

333 = n - 1

n = 333 + 1

n = 334

Sn = n/2 (2a + (n-1)d)

$= \frac{334}{2} (2(222) + (334 - 1)2) \\ = 167(444 + 666) \\ = 167 \times 1110 \\ = 185370$

hope you get your answer