Question

sum of the sides of two suqares is 400cm2. If the difference of their perimeters is 16 cm, find the sides of the squares

Answer 1

ATQ,

sum of the sides of two squares is 400cm and the difference between their perimeter is 16cm.

let the sides of the squares be x and y respectively.

➡ x + y = 400cm -------(i)

perimeter of a square = 4 × side

➡ 4x - 4y = 16cm -------(ii)

applying substitution method,

from equation (i) we get,

➡ x = 400 - y

putting value of x from equation (i) in equation (ii)

➡ 4(400 - y) - 4y = 16cm

➡ 1600 - 4y - 4y = 16cm

➡ -8y = 16 - 1600

➡ -8y = -1584

➡ y = -1584/-8

➡ y = 198cm

now, we've found the value of y let's put the value of y in equation (i)

➡ x + 198 = 400cm

➡ x = 400 - 198

➡ x = 202cm

hence, the sides of the squares are 202cm and 198cm respectively.

Answer 2

Answer:

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