Question

sum of the square of two consecutive odd positive integers in 290, find them​

Answer 1

Step-by-step explanation:

Let the two consecutive odd positive integers be x and x + 2

Now it is given that the sum of the squares is 290.

⇒ x² + ( x + 2 )² = 290

⇒ x² + x² + 4x + 4 = 290

⇒ 2x² + 4x + 4 – 290 = 0

⇒ 2x² + 4x – 286 = 0

Dividing by 2 we get,

⇒ x² + 2x – 143 = 0

⇒ x² + 13x – 11x – 143 = 0

⇒ x ( x + 13 ) -11 ( x + 13 ) = 0

⇒ ( x – 11 ) ( x + 13 ) = 0

⇒ x = -13, 11

Good Night

Answer 2

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