Question

Sum of the square of two consecutive positive even integers is 100, find

those numbers by using quadratic equation.​

Answer 1

Answer:

(−8,−6) OR (6,8)

Step-by-step explanation:

Let x and (x+2) be the consecutive even integers. We get

x ^2 + (x+2) ^2 = 100

expanding, we get

x ^2 + x ^2 + 4x +4 = 100

setting = 0, we get

2x ^2 + 4x − 96 = 0

Dividing by 2 , we get,

x ^2 + 2x − 48 = 0

factoring, we get,

(x+8)(x−6)=0

solving for x, we get

x+8=0 = x=−8

and x−6=0=x=6.

so, we have

(−8,−6) OR (6,8)

hope it will be useful