Question

sum of the square of two consecutive positive even integers is 100 find two. number using quadratic equations ​

Answer 1

Answer:

36 64

Step-by-step explanation:

x^2 + (x+2)^2 = 100

x^2 + x^2 + 4x + 4 = 100

2x^2 + 4x +4-100=0

2x^2 +4x -96=0

2x^2 + 16x -12x -96=0

2x(x +8) -12(x +8)=0

(2x - 12)(x +8)

2x -12 =0

2x = 12 ; x = 6

x +8 = 0

x = -8

Therefore 1st Number =6^2 = 36

& 2nd Number = 8^2 = 64

Since we are said that the numbers are positive even .we can't take the other number -8