sum of the squares of 2 consecutive natural odd numbers is 394. Find the numbers
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Answer:
Let the odd natural number be 'x' so
Hence the consecutive odd natural number will be 'x+2'
Hence the equation would be,
x^2+x^2+4x+4=394
2x^2+4x-390=0
By Splitting the middle term we get,
2x^2-26x+30x-390=0
2x(x-13) +30(x-13)=0
(2x+30) (x-13) =0
Hence,
x=-30/2 or 13
Since it is given that 'x' is a natural number
x=13
x+2=15
Hence the two consecutive odd natural numbers are 13 and 15
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