Question

sum of the squares of first n natural number​

Answer 1

Step-by-step explanation:

Sum of squares of n natural numbers

n×(n+1)×(2n+1)6 n × ( n + 1 ) × ( 2 n + 1 ) 6

Hope it helps you

Answer 2

Answer:

The formula to find sum of first and terms of a sequence of square of natural numbers = 6n(n+1)(2n+1)