Question

Sum of the squares of two consecutive odd natural numbers is 202. Using this we can form a second degree equation in the form ax² +bx+ c = 0 . which number comes in the place of ' c ' ?​

Options
_________
a) 202
b) 198
c) -198

Answer 1

Answer:

C)-198

Step-by-step explanation:

let first no =X

2nd odd no =X+2

x²+(x+2)²=202

x²+x²+2x+4=202

2x²+2x+4-202=0

2(x²+x-198)=0

x²+x-198=0

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Answer 2

Question :-

• Sum of the squares of two consecutive odd natural numbers is 202. Using this we can form a second degree equation in the form ax² +bx+ c = 0 . which number comes in the place of ' c ' ?

To find :-

• Which number comes in the place of 'c' ?

$\large{ \sf{ \underline{Solution - }}}$

Let us assume the first nunber be 'x'

$\sf{According \: to \: question : }$

$\bold{2nd }\: \sf {odd \: number}$

$\large{ =} \: \sf{ x }+ \bold{ 2}$

$\large{ ↦ \: } \: \sf{ {x}^{2} } \: \small{ \: + \: } \: \: \sf{(x} \small \: \: { + } \: \bold{2)} {}^{2} \large {= 202}$

$\large{ ↦ \: \: } \sf{ {x}^{2} } \small{ \: \: + } \: \: \large{\sf{ {x}^{2} }} \: \small{ \: \: + } \: \: \: \large{2x} \: \: \small{ \: \: + } \: \: \: \: \large{4 = 202}$

$\large{↦ \: \: } \large{\sf{2x {}^{2}} } \small \: { + \: \: } \sf{\large{2x}} \small \: \: { \: +} \: \: \large{ \sf{4}} \small{ \: \: - \: \: } \: \large{202 = 0}$

$\large{↦ \: } \: \sf{2(x {}^{2} \small{ \: \: + } \: \: \sf{ \large{x}}} \: \small{ \: \: - } \: \: \sf{ \large{198)}} \large{ \bold{ = 0}}$

$\large{↦ \: } \: \sf {x}^{2} \: \: \small{ + } \: \: \sf{ \large{x}} \: \: = \: \large{198}$

Answer : 198