sum of the squares of two numbers is 208. Difference of the two number is 4.Find the numbers.
Answers
Answer:
Step-by-step explanation:
let the numbers be x,y (x>y)
here x2=18y
according to the problem
x2+y2=208....................(1)
18y+y2=208
y2+18y-208=0
y2+26y-8y-208=0
y(y+26)-8(y+26)=0
(y+26)(y-8)=0
as the numbers are +ve
y-8=0
y=8
substitute y in (1)
x2+(8)2=208
x2+64=208
x2=208-64
x2=144
x=12
the nos. are 12,8 let the numbers be x,y (x>y)
here x2=18y
according to the problem
x2+y2=208....................(1)
18y+y2=208
y2+18y-208=0
y2+26y-8y-208=0
y(y+26)-8(y+26)=0
(y+26)(y-8)=0
as the numbers are +ve
y-8=0
y=8
substitute y in (1)
x2+(8)2=208
x2+64=208
x2=208-64
x2=144
x=12
the nos. are 12,8
Answer:
Step-by-step explanation:
let the no are x and x+4
x^2+(x+4)^2=208
x^2+x^2+16+8x=208
2x^2+8x-192=0
x^2+4x-96=0
(x+12)(x-8)=0
x=-12,x=8
if x=-12 then other no=-8
if x=-8 then other no=12
so no are 8,12 or -12,-8