sum of the terms of ap a,2a,3a,4a............10a.s10 is
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Answer:
10a^2+9a
Step-by-step explanation:
Sum=n/2(2a+n-1)d
n=2
a=a( a is the first term of an AP)
d=a(d is the common difference)
=10/2(2a+9)a
=5×2a^2+9a
=10a^2+9a
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