Question

sum of the the squres of the zeroes of the polymial p(x)=x²+7x-k is 25 find k​

Answer 1

Answer:

- 12.

Step-by-step explanation:

P(x) = x²+7x-k

Let A and B are the zeroes of quadriatic

polynomial then,

sum of zeroes (A+B) = (-coefficient of x)/coefficient of x^2

= -7/1 = -7.

And, product of zeroes.

(A*B) =. constant term/coefficient of x^2

= -k/1 = -k.

we have,

A^2+B^2= (A+B)^2 - 2AB

~49+2K=25

~k= (25-49)/2 =(-24)/2 = -12

THIS IS THE REQUIRED ANSWER.

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