Question

Sum of the three consecutive term of an ap is 42 and product of first and last terms is 180.find the terms

Answer 1

Let the 3consecutive terms of an AP = (a-d), a, (a+d)

(a-d) + a + (a+d) = 42

3a = 42

a = 42/3 = 14   ...............(1)

(a-d) (a+d) = 180  (given)

a² -  d²  = 180

14² - d² = 180

d² = 196 - 180 = 16

d = 4   --------- (2)

So the terms are

(14-4), 14, (14+4)

10, 14, 18