sum of the two digit number is 11 if the number obtained by reversing the digit is 9 less than the original number find the number
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The number is 65.
Let the digits be x and 11-x.
No. is 10(x) +(11-x) i.e. 9x+11
No. by reversing digits is 10(11-x) + (x) i.e. 110-9x
9x + 11 -(110-9x) = 9
18x = 108
x= 6
Therefore number is (9x6)+11 = 65.
Let the digits be x and 11-x.
No. is 10(x) +(11-x) i.e. 9x+11
No. by reversing digits is 10(11-x) + (x) i.e. 110-9x
9x + 11 -(110-9x) = 9
18x = 108
x= 6
Therefore number is (9x6)+11 = 65.
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