sum of the two digit number is 9 the number formed by interchanging the order of the digit is 27 more than the given number.find the number
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let no.is 10y+x
then sum of two digit no.is x+y = 9
now after interchanging the digits.=
10x+y+27=10y+x
9x-9y=-27
y-x=3
and eq.2nd is y+x=9
solve these eq.X=3
y=6 and no.is. 63
then sum of two digit no.is x+y = 9
now after interchanging the digits.=
10x+y+27=10y+x
9x-9y=-27
y-x=3
and eq.2nd is y+x=9
solve these eq.X=3
y=6 and no.is. 63
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