Question

sum of the two numbers are 15 and sum of their recipocal is 3/10 finde two numbers

Answer 1

Answer:

Step-by-step explanation:

let the two numbers be A and B

=>A+B=15                      .............(1)

and

1/A +1/B=3/10

⇒(A+B)/AB = 3/10

from (1)

(A+B)/AB = 15/AB

⇒15/AB = 3/10

⇒AB = 50        ............(2)

solving (1) and (2)

A = 10 and B = 5

or

A = 5 and B = 10

Plz brainliest

Answer 2

Let one number be x and other be y.
x+y=15
x=15-y -->[1]

1/x +1/y =3/10
y+x/xy=3/10
10y+10x=3 (xy)
3 (15-y (y))-10y-10 (15-y)=0
3 (15y-y^2)-10y-150+10y=0
45y-3y^2-150=0
3y^2-45y+150=0 ÷3
y^2 - 15y + 50=0
y^2-10y-5y+50=0
y (y-10)-5 (y-10)=0
(y-10)(y-5)=0
y-10=0 y-5=0
y=10 y=5
The two numbers are 10 and 5.