Sum of the two numbers is 51. If one of the numbers exceed the other number by 11, then find
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Answer:
sum of both no.= 51 let the first no. be x
the second no. = x+11
sum= x+x+11= 51
2x+11=51
2x=51-11
2x=40
x= 40/2
x= 20
so, the first no. is 20 and the second no. is 31.
Answered by
0
Step-by-step explanation:
let 'x' and 'y' be a two number.
According to the question
x+y = 51.........(1)
also first number is exceed the other number by 11
x= y+11.........(2)
using equation (2) in equation (1)
( y+11) + y = 51
2y +11 =51
2y = 51 -11
2y = 40
y = 40/2
y =20
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