Question

sum of the two numbers is 52 if second number is 10 more than first , find the number.​

Answer 1

Answer:

x=21

x+10=31

Step-by-step explanation:

let the first number be x

let the second number be x+10

Therefore,

1st number= x

2nd number= x+10

The equation will be,

x+ (x+10) = 52

x+x+10= 52

2x+10= 52

2x= 52-10

2x=42

x=42/2

x= 21

Therefore, x=21 (first number)

x+10=21+10= 31 (second number)

The first number is 21

The second number is 31

Answer 2

Answer:

$sum \: = 52$

$\: 1 \: number = \: x$

$2nd \: number = \: x + 10$

$x + (x + 10) = 52$

$x + x + 10 \: = 52$

$2x = 52 - 10$

$2x = 42$

$x = \frac{42}{2} = 21$

$smaller \: no. \: = 21$

$2nd \: number \: = x + 10 \\ 21 + 10 = 31$