Sum of the two zeroes of a polynomial of degree 4 is - 1 and their product is - 2 . If other two zeroes are root 3 and - root 3, then find the polynomial
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Sum of the two zeros of a polynomial of degree 4 is -1 and their product is -2. If the other two zeros are root3 and -root3, find the polynomial
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Answer:
Required polynomial p(x)=x⁴-3x²+x³-5x²-3x+6
Explanation:
Let 4 th degree polynomial be p(x)
It is given that sum of the two zeroes of a polynomial of degree 4 is -1 and their product is -2 .
Other two zeroes are √3 and -√3 .
i ) If we can find two numbers p and q such that
p+q = -1 ---(1)
and
pq = -2 ---(2)
then we can the factors.
(p-q)² = (p+q)²-4pq
= (-1)²-4(-2)
= 1+8
= 9
Now ,
p-q = √9
=> p-q = √3²
=> p-q = 3 ---(3)
Add equations (1) & (3) , we get
2p = 2
=> p = 1 ---(4)
Substitute p=1 in equation (2), we get
q = -2 ---(5)
Therefore,
1,-2 , √3 , -√3 are four factors of p(x)
=> p(x) = (x-1)(x+2)(x-√3)(x+√3)
= (x²+2x-x-2)[x²-(√3)²]
= (x²+x-2)(x²-3)
= x⁴-3x²+x³-3x-2x²+6
= x⁴+x³-5x²-3x+6
Therefore,
Required polynomial p(x)=x⁴-3x²+x³-5x²-3x+6
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