Question

Sum of the zeroes of a quadratic polynomial is b/a c/a d/a -b/a

Answer 1

Given: p(x)= ax^2 + bx - 4..........(p)

\alpha + \beta = \frac{1}{4}α+β=

4

1

\alpha \times \beta = 1α×β=1

To Find : values of a and b

solutions :-

formula of quadratic equation:-

p(x) = a[x^2 - (sum of zeros)x + product of zeros]

Now:-

p(x) = a[x^2 - (1/4)x + 1]

p(x) = a[x^2 - 1/4x + 1]..........(q)

Now:- by comparing (p) and (q)

a = 1

b = -1/4

Answer 2

Answer:

-b/a is the right answer hope it helps