Sum of the zeroes of the polynomial p(x) = x2 - kx + 9 is 7. Find ti
value of K.
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The required value of k is 7.
Given:
Sum of zeroes=7
p(x)= x2-kx+ 9
To find:
The value of k
Solution:
The given polynomial has coefficients of and x that will be used to obtain the sum of its zeroes.
The coefficient of and x are a and bb, respectively.
So, a=1 and b= -k
We know that the sum of zeroes= -b/a
Using the given value of the sum,
-(-k)/1=7
k/1=7
k=7
Therefore, the required value of k is 7.
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