Question

Sum of the zeros of the polynomial p(x)=x^2+7x+10

Answer 1

Answer:

-7

Step-by-step explanation:

${x}^{2} + 7x + 10 = 0$

Here,

a = co efficient of x^2 = 1

b = co efficient of X = 7

c = constant term = 10

sum of zeroes of polynomial,

$\alpha + \beta = \frac{ - b}{a}$

$= \frac{ - 7}{1}$

$= - 7$

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Answer 2

Answer:

Answer:

-7

Step-by-step explanation:

{x}^{2} + 7x + 10 = 0x

2

+7x+10=0

Here,

a = co efficient of x^2 = 1

b = co efficient of X = 7

c = constant term = 10

sum of zeroes of polynomial,

\alpha + \beta = \frac{ - b}{a}α+β=

a

−b

= \frac{ - 7}{1}=

1

−7

= - 7=−7

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