Question

sum of the zeros of the polynomial p (x) = x square - kx + 9 is 7. Find the value of k.​

Answer 1

Let's solve for K.

$px=x^2kx+9is(7)$

Step 1: Flip the equation.

$kx^3+63-is=px$

Step 2: Add -kx^3 to both sides.

$kx^3+63is+−kx^3=px+−kx^3$

$63-is=−kx^3+px$

Step 3: Divide both sides by 63s.

$63-is-63s=−kx^3+px 63s$

$i=−kx^3+px 63s$

Answer:

$→K=−kx^3+px 63s$