Sum of those integers from 1 to 500 which are multiples of 2 or 5
Answers
Answered by
1
Answer:
12750
Step-by-step explanation:
no.of terms =50
a=10
d=2*5=10
sn=n/2(2a+(n-1)d)
=50/2(2*10+(50-1)10)
=25(20+49*10)
=25(20+490)
=25*510
=12750.
Hope this will be helpful. Sorry if there is any mistake in the solution
arpitasahani:
Ur ans is wrong
Answered by
0
the integers which are divisible by 2 and 5 both are 10 20 30 40 50 60 70 80 90 100 110 120 130-140 150-160 170-180 190-200 210 220 230-240 250 260 270 280-290 300 310 320-330 340 350 360 370 380 390 400 410 420 430 440 450 460 470 480 490 500
probability of getting an divisible by 2 and 5 both integers
= number of favourable event/ total number of event
=here number of favourable events are 50 and total number events are 500
So,
=50/500
=1/10
probability = 1/10
Similar questions