Question

Sum of thousand is in the form of denominator of rupees 20 and 10 of the total number of notes 60, find the number of ₹20notes ​

Answer 1

$\large\sf \purple{ \underline{Let:- }}$

$\implies \mathtt{No. \: of \: ₹ 10 \: notes \: as \: 'x' }$

$\implies \mathtt{No. \: of \: ₹ 60 \: notes \: as \: 'y' }$

$\large \sf \purple{ \underline{Given:-}}</p><p>$

$\implies \mathtt{Total \: sum= ₹1000}$

$\implies \mathtt{Number \: of \: notes= 60}$

$\large \sf \purple {\underline{Solution:- }}</p><p>$

$\implies \bf{∴x+y=60}$

$\implies \bf{∴x=60-y \: ━━ \: Eq. 1}$

$\implies \bf{10x+50y=1000 \: ━━ \: Eq.2}$

$\mathtt {Substituting \: \: Eq.1 \: in \: Eq.2 :- }$

$\implies \bf{10(60-y) + 50y =1000</p><p>}$

$\implies \bf{</p><p>600-10y+50y=1000}$

$\implies \bf{40y=1000-600}$

$\implies \bf{40y=400}$

$\implies \bf{y=10}$

$\mathtt{So \: now \: for \: x:- }$

$\implies \bf{x=60-y}$

$\implies \bf{x = 60 - 10}$

$\implies \bf{x=50}$

• No. of 10 Rupees notes:- 50
• No. of 60 Rupees notes :- 10
• Total :- 60 notes

Answer 2

Answer :-

We let ,

• No. of Rupees 10 notes = x
• No. of Rupees 60 notes = y

Given :-

Total sum ↠ $Rupees 1000$

Number of notes ↠ 60

SoLuTioN :-

• x+y=60

• x=60-y ━━ Eq. 1

⇒ {10x+50y=1000 ━━ Eq.2

Substituting Eq.1 in Eq.2 :

⇒ {10(60-y) + 50y =1000}

⇒ {600-10y+50y=1000}

⇒ {40y=1000-600}

⇒ {40y=400}

⇒ y = 10

So, now for x:-

{x=60-y}

x = 60 - 10

⇒ x = 50

➤ No. of 10 Rupees notes:- 50

➤ No. of 60 Rupees notes :- 10

Total :- 60 notes

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