Sum of three angles of a triangle ABC is 180 degree. The ratio of angle BAC, angle ABC and angleACB is 3:5:10 . If the value of angle BAC is decreased by 10 degree and the value of angle ABC is increased by 10 degree . Let’s calculate the new ratio of the three angles .
Answers
Answer:
the new ratio of the three angles (i.e. angle BAC, angle ABC and angle ACB ) = 1:3:5.
Step-by-step explanation:
ratio of the three angles = 3:5:10.
let, angle BAC = 3x
angle ABC = 5x
angle ACB = 10x.
so, 3x +5x+10x=180.
18x =180.
x = 10.
therefore, angle BAC=30°
Angle ABC= 50°
Angle ACB = 100°
value of angle BAC is decreased by 10°, so, angle BAC = 20°
value of angle ABC is increased by 10°,. so, angle ABC= 60°
So, ratio of angle BAC, angle ABC and angle ACB = 20:60:100
= 1:3:5.
Let each ratio be multiplied by x.
angle BAC=3, angle ABC=5,angle ACB=10
SO, angle BAC=3*X=3X
angle ABC=5*X=5X
angle ACB=10*X=10X
SUM OF THE ANGLES IN A TRIANGLE IS EQUAL TO 180 DEGREES
3X+5X+10X=180 DEGREES
18X =180
X=180/18
=10
THEREFORE, ANGLE BAC =3*X=3*10
=30 DEGREES
ANGLE ABC=5*10
= =50 DEGREES
ANGLE ACB=10*10 =100 degrees
condition: the value of angle BAC is decreased by 10 degrees and the value of angle ABC IS increased by 10 degrees, we get
THEREFORE, angle BAC=3O DEGREES -10
=20 DEGREES
angle ABC becomes 50+10 =60 degrees
therefore the ratio becomes
20:60:100
2:6:10