Question

sum of three colnsective integer is 24 find the integer
​

Answer 1

Given:-

• Sum of three consecutive integer is 24.

⠀

To find:-

• The integer.

⠀

Solution:-

Let,

• the three consecutive integers be x, x + 1, x + 2.

⠀

According to the question

→ x + (x + 1) + (x + 2) = 24

→ 3x + 3 = 24

→ 3x = 24 - 3

→ 3x = 21

→ x = 21/3

→ x = 7

⠀

Hence, the three consecutive integers are:-

• x = 7
• x + 1 = 7 + 1 = 8
• x + 2 = 7 + 2 = 9

⠀

Verification:-

→ 7 + 8 + 9

→ 15 + 9

→ 24

Hence Verified

Answer 2

Answer:

• The three integers are 7, 8 and 9.

Step-by-step Explanation:

$\normalsize\underline{\bf{Given:}}$

$\:\:\:\:\normalsize{\sf{The\:sum\:of\:three\: integers\:is\:24}}$

$\:\:\:\:\normalsize{\sf{And\:the\:three\: integers\:are\: consecutive.}}$

‎

$\normalsize\underline{\bf{To\:find:}}$

$\:\:\:\:\normalsize{\sf{The\:three\: integers}}$

‎

$\normalsize\underline{\bf{Solution:}}$

$\normalsize{\sf{Let,\:the\:three\: consecutive\: integers\:be:}}$

• $\large{\tt{\red{(p)}}}$
• $\large{\tt{\red{(p+1)}}}$
• $\large{\tt{\red{(p+2)}}}$

$\normalsize{\bf{According\:to\:the\: given\:question:}}$

$\:\:\:\:\:\large{\tt{p+(p+1)+(p+2)=24}}$

$\large\implies{\mathrm{3p+3=24}}$

$\large\implies{\mathrm{3p=24-3}}$

$\large\implies{\mathrm{3p=21}}$

$\large\implies{\mathrm{p=\cancel{\frac{21}{3}}}}$

$\:\:\:\:\:\:\:\:\:\:\:\Large\implies{\boxed{\tt{p=7}}}$

$\normalsize{\bf{So,}}$

• $\large{\sf{p= \red{\underline{7}}}}$
• $\large{\sf{(p+1)=7+1= \red{\underline{8}}}}$
• $\large{\sf{(p+2)=7+2= \red{\underline{9}}}}$

‎

$\normalsize\underline{\bf{Verification:}}$

$\normalsize{\sf{Sum\:of\:three\: consecutive\:integers=24}}$

$\normalsize\longrightarrow{\mathrm{7+8+9=24}}$

$\normalsize\longrightarrow{\mathrm{24=24}}$

$\normalsize\longrightarrow{\sf{L.H.S=R.H.S}}$

$\normalsize\longrightarrow\underline{\bf{Hence,\: verified!}}$

‎

$\normalsize\underline{\bf{Final\:answer:}}$

$\normalsize\therefore\underline{\boxed{\tt{\pink{The\: three\:integers\:are\:7,\:8\:and\:9.}}}}$

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