Question

sum of three consecutive even number is 68 more than average of the numbers find the middle numbers

Answer 1

let take that consecutive even numbers as
x, x+2,x+4

(x)+(x+2)+(x+4) = (x)+(x+2)+(x+4)/3 + 68
x+x+2+x+4 = x+x+2+x+4/3 + 68
3x+6 = 3x+6/3 + 68
3x+6 = 3(x+2)/3 + 68
3x+6 = x+2+68
3x+6 = x+70
3x-x = 70-6
2x = 64
x = 64/2
x = 32

so the consecutive even number are
x = 32
x+2 = 32+2 = 34
x+4 = 32+4 = 36

so the middle numbers should be odd numbers so
x+1 = 32+1 = 33
x+3 = 32+3 = 35