Question

sum of three consecutive even numbers is 198. find the numbers. what is the numbers?

Answer 1

Let the first even no. be 'x'
The second even no. be x+2
The third even no.  be  x+4
A/q, 
x + x+2 + x+4  =  198
3x + 6 = 198
3x = 192
x = 64
Therefore, the first no. is 64
the second no. is x+2 = 64+2 = 66
the third no. is x+4 = 64+4 = 68

Answer 2

Here is your solution

Given:-

sum of three consecutive even numbers is 198

Let
Number be x,x+2,x+4

Now

A/q

x+(x+2)+(x+4)=198
3x+6=198
3x=198-6
3x=192
x =64

Hence Number are:-
x=64
x+2=64+2=66
x+4=64+4=68

The three consecutive even numbers are,64,66,68.

Hope it helps you