Question

Sum of three consecutive even numbers is 54. Find the numbers.

Answer 1

Answer:

Here is your solution

Let,

The first even integer be:x

Then the second even integer is:x+2

Then the third even integer is: x+2+2=x+4

Sum of three consecutive even numbers =54

A/q

(x)+(x+2)+(x+4)=54

3x+6=54

3x=54-6

3x=48

x=16

now

The first integer is:x=16

the second integer is:x+2=16+2=18

the third integer is: x+4=16+4=20

Hope it helps you

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Answer 2

Answer:-

$\red{\bigstar}$ The numbers are

$\large\leadsto\boxed{\rm\purple{16}}$

$\large\leadsto\boxed{\rm\purple{18}}$

$\large\leadsto\boxed{\rm\purple{20}}$

• Given:-

Sum of three consecutive even numbers is 54.

• To Find:-

The numbers

• Solution:-

Let the three consecutive even numbers be n,n+2,n+4.

• According to the question:-

→ $\sf n + (n+2) + (n+4) = 54$

→ $\sf n + n + 2 + n + 4 = 54$

→ $\sf 3n + 6 = 54$

→ $\sf 3n = 54 - 6$

→ $\sf 3n = 48$

→ $\sf n = \dfrac{48}{3}$

$\pink{\bigstar}$ $\large{\underline{\underline{\bf\green{16}}}}$

Now,

• n = 16

• n+2 → 16+2 = 18

• n+4 → 16+4 =20

Therefore, the numbers are 16,18 and 20.

$\pink{\bigstar}$ Verification:-

→ 16 + 18 + 20

→ 34 + 20

→ 54

★ HENCE VERIFIED★