Question

SUM OF THREE CONSECUTIVE INTEGERS 96

Answer 1

Answer:

According to the question,

Let the number be x, so that

x + x + 1 + x + 2 = 96

or, 3x + 3 = 96

or, x = 96-3/3 = 93/3 = 31

x + 1 = 31+1 = 32

x + 2 = 31+2 = 33

So, the three integers are 31,32,33.

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Answer 2

Answer:

let the integers be x- 1, x and x + 1

according to question ,

x- 1 + x + x + 1 = 96

=> 3x = 96

=> x = 96/3

=> x = 32

so,

first integer = x -1 = 32 - 1 = 31

second integer = x = 32

third integer = x + 1 = 32 + 1 = 33

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