Question

sum of three consecutive integers is 24 .find the integers​

Answer 1

Step-by-step explanation:

Let the 1st integer be x

the 2nd integer be x + 1

the 3rd integer be x + 2

A/Q,

x + x + 1 + x + 2 = 24

3x + 3 = 24

3x = 24 - 3

3x = 21

x = 21 ÷ 3

= 7

THEREFORE , INTEGERS = 7, 7+1 = 8 , 7 + 2 = 9

Answer 2

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sum of three consecutive integers is 24. Find the integers?

$\huge{ \red{ \underline{ \underline{ \mathfrak{ \color{orange}{answer}}}}}}$

$\tt \blue{integers = 8}$

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$\tt{let \: the \: integers \: be \: x}$

$\tt{ sum =24 \} \: given}$

$\tt{ \to \: x + x + x = 24}$

$\tt{ \to3x = 24}$

$\tt{ \to \: x = \frac{ \cancel{24} ^{8}} { \cancel{3} ^{1} } }$

$\tt{ \to \: x = 8}$

$\tt \red{ \therefore \: integers = 8}$

$\huge{ \underbrace{ \green{ \mathfrak{verification}}}}$

$\tt{ \to \: x + x + x = 24}$

$\tt{if \: x = 8}$

$\tt{ \to8 + 8 + 8 = 24 }$

$\tt{ \to24 = 24}$

$\bold{\boxed{ \mathfrak{ \red{verified}}}}$