Question

Sum of three consecutive integers is 33. What is the largest among the three consecutive integers?

Answer 1

AnswEr :

Let the three consecutive numbers be,

• x

• x + 1

• x + 2

Now, it is given that, sum of three consecutive integers is 33. So,

According to the given condition,

$\longrightarrow \sf \: x + (x + 1) + (x + 2) = 33 \\ \\ \longrightarrow \sf \:3x + 3 = 33 \\ \\ \longrightarrow \sf \:3x = 33-3 \\ \\ \longrightarrow \sf \:3x = 30 \\ \\ \longrightarrow \sf \:x = \cancel{\dfrac{30}{3}} \\ \\ \longrightarrow \sf \:{ \underline{ \boxed{ \textbf{ \textsf{x = 10}}}}} \: \: \bigstar$

So, the required value of x is 10.

Hence, the integers are :

• 1st integer : x = 10

• 2nd integer : x + 1 = 10 + 1 = 11

• 3rd integer : x + 2 = 10 + 2 = 12

Therefore, 3rd integer is the largest among all the integers.

Additional information :

⠀• Integer is a number which doesn't ⠀⠀has any fraction.

⠀• Also, it can be a whole number.

⠀• Example : 1, 8, 3, & −186 are integers.