Math, asked by simcard3621, 9 months ago

Sum of three consecutive integers is 51 . The middle one is:

A) 14 B) 15 C) 16 D) 17

Answers

Answered by Anonymous
9

Let ,

The three consecutive integers are

" x " , " x + 1 " , and x + 2

According to the question ,

The sum of three consecutive integers is 51

Thus ,

x + x + 1 + x + 2= 51

3x + 3 = 51

3x = 48

x = 16

  \therefore \sf \underline{The  \: middle \:  number  \: is \:  17}

Answered by srutisumani
4

Answer:

the answer is Option D that is 17..

Step-by-step explanation:

first no.=x

second no.=x+1

third no.=x+2

sum of three consecutive integer=51

so,according to question=

x+x+1+x+2=51

3x+3=51

3x=51-3

3x=48

x=48÷3

x=16

so,x=16,x+1=17,x+2=18

if you want the middle one then;x+1=17..(ans)

Hope it helps you mate!!

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