Question

Sum of three consecutive integrers is 24. Find the integers

Answer 1

X+X+1+x+2 = 24
3X+3 = 24
3X = 24-3
3X =21
X = 21/3
X = 7
so , the three consecutive integers are 7,8,9.

Answer 2

let the first number be x
second number be x+1
third number be x+2
according to question
x+x+1+x+2= 24
3x+3=24
x+1=24/3
x+1 = 8
x=7
first number is 7
second number is 8
third number is 9