Math, asked by dhanu, 1 year ago

sum of three consecutive intergers is 48. find the even number

mishti: one number is even=2x.

mishti: one number is even=2x
other 2 are odd= (2x+1) and (2x-1)
so, (2x+1) + 2x + (2x-1)=48
2x+2x+2x=48
6x=48
x=8.
so the three numbers are= 15,16,17.

jayant: Let first no. be x. Then second would be x+1 and third would be x+2 .

jayant: Now, x+(x+1)+(x+2)=48
i.e. 3x+3=48
or,3x=48-3=45

jayant: Therefore, x=15
So, the three consequtive numbers are 15,16,17 out of which only 16 is even.

Answers

Answered by girishkumar325girish

let the consecutive integers be x,x+1,x+2 so x+x+1x+2=48 then x=15 so numbers are 15,16,17 so the even number is16

Answered by HappiestWriter012

Hey there!
Let the three consecutive integers be x, x + 1 , x + 2 .

So,

=> x +( x + 1) + ( x + 2 ) = 48

=> 3x + 3 = 48

=> 3x = 45

=> x = 15

The three numbers are,
x =15
x + 1 = 15 + 1 = 16
x + 2 = 15 + 2 = 17 .

Here, 16 is divisible by 2 . So, 16 is the required even number.

Therefore, Among the three consecutive numbers, 16 is the even number.

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