sum of three consecutive multiple of 11 is 363 find multiples
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Answered by
4
Let the numbers be x, x+11,x+22
Then x+x+11+22+x=363
3x+33=363
3x=363-33
3x=330
x=360/3=110
Then the multiples will
110,110+11=121,110+22=132
Main answer is 110,121,132
Then x+x+11+22+x=363
3x+33=363
3x=363-33
3x=330
x=360/3=110
Then the multiples will
110,110+11=121,110+22=132
Main answer is 110,121,132
akc7:
wrong calculation
Answered by
0
Answer: 110 , 121 and 132
Step-by-step explanation:
Let the number's be x , x+11 , x+22.
x + x + 11 + x + 22 = 363
3x + 33 = 363
3x = 363 - 33 = 330
x = 330/3 = 110
x + 11 = 110 + 11 = 121
x + 22 = 110 + 22 = 132
Hence, the number's are 110 ,121 and 132.
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