sum of three consecutive multiple of 4 is 108 . find the number
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let the no. be x
Then three no. are x,x+4,x+8
x+x+4+x+8=108
3x+12=108
3x=108/12=9
x=9/3=3
x=3
x+4=3+4=7
x+8=3+8=11
Three no. are 3,7and 11
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